((4/3)*3.14159265359*(1.2+0.01x)^3)=1980/2700

Solution for ((4/3)*3.14159265359*(1.2+0.01x)^3)=1980/2700 equation:

((4/3)*3.14159265359(1.2+0.01x)^3)=1980/2700

We move all terms to the left:

((4/3)*3.14159265359(1.2+0.01x)^3)-(1980/2700)=0


Domain of the equation: 3)*3.14159265359(1.2+0.01x)^3)!=0

x∈R


We add all the numbers together, and all the variables

((+4/3)*3.14159265359(0.01x+1.2)^3)-(+1980/2700)=0

We get rid of parentheses

((+4/3)*3.14159265359(0.01x+1.2)^3)-1980/2700=0

We calculate fractions


(-17820x^2)/3*3.14159265359(0.01x)+()/3*3.14159265359(0.01x)=0

We add all the numbers together, and all the variables

(-17820x^2)/3*3.14159265359(+0.01x)+()/3*3.14159265359(+0.01x)=0

We multiply all the terms by the denominator


(-17820x^2)+()=0

We add all the numbers together, and all the variables

(-17820x^2)=0

We get rid of parentheses

-17820x^2=0

a = -17820; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-17820)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-35640}=0$